-[z-(4z+2)]=2+(2z+7)

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Solution for -[z-(4z+2)]=2+(2z+7) equation:


Simplifying
-1[z + -1(4z + 2)] = 2 + (2z + 7)

Reorder the terms:
-1[z + -1(2 + 4z)] = 2 + (2z + 7)
-1[z + (2 * -1 + 4z * -1)] = 2 + (2z + 7)
-1[z + (-2 + -4z)] = 2 + (2z + 7)

Reorder the terms:
-1[-2 + z + -4z] = 2 + (2z + 7)

Combine like terms: z + -4z = -3z
-1[-2 + -3z] = 2 + (2z + 7)
[-2 * -1 + -3z * -1] = 2 + (2z + 7)
[2 + 3z] = 2 + (2z + 7)

Reorder the terms:
2 + 3z = 2 + (7 + 2z)

Remove parenthesis around (7 + 2z)
2 + 3z = 2 + 7 + 2z

Combine like terms: 2 + 7 = 9
2 + 3z = 9 + 2z

Solving
2 + 3z = 9 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
2 + 3z + -2z = 9 + 2z + -2z

Combine like terms: 3z + -2z = 1z
2 + 1z = 9 + 2z + -2z

Combine like terms: 2z + -2z = 0
2 + 1z = 9 + 0
2 + 1z = 9

Add '-2' to each side of the equation.
2 + -2 + 1z = 9 + -2

Combine like terms: 2 + -2 = 0
0 + 1z = 9 + -2
1z = 9 + -2

Combine like terms: 9 + -2 = 7
1z = 7

Divide each side by '1'.
z = 7

Simplifying
z = 7

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